1: If the exponent on the numerator is high that the exponent in the denomanator then the limit, when approching infinity is infinity.
lim_x-infinity 4x^5-3x+1/2x^2+5x-3, the limit=infinity
2: When the exponents are the same in both the numerator and the denominator the you take the ratio of the coefficients to find the limit.
lim_x-infinity 4x^2-3x+1/2x^2+5x+3=4/2=2
3: And lastly when the denominator has the higher exponent the limit is zero.
lim_x-infinity 4x^2-3x+1/2x^5+5x+3=0
Sorry if i said something incorrect about limits. i'm still a little new at this.
(For some reason when i made the post i couldn't get the equation editor)
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